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8k^2+7k-46=0
a = 8; b = 7; c = -46;
Δ = b2-4ac
Δ = 72-4·8·(-46)
Δ = 1521
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1521}=39$$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-39}{2*8}=\frac{-46}{16} =-2+7/8 $$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+39}{2*8}=\frac{32}{16} =2 $
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